4
You're allowing the attacker to use any arbitrary input, so they can inject extra parameters, etc. I think what the security scanner is looking for is EncodingUtil.urlEncode:
String url = '/' + oGenericObj.getDescribe().getKeyPrefix() + '/e';
if (strObject.equals('Quote')) {
url += '?oppid=' +
EncodingUtil.urlEncode(
System....
3
You can use the Safe Navigation Operator (?.) to avoid null checks:
String someValue = inputParam?.objectHere?.someProperty;
This is likely the best choice in many cases, unless you need to actually use the object for output, then you might want to go with Derek's answer.
3
I don't believe there is a way to initialize class variables without writing code to explicitly set those variables.
That's not just a JSON deserialization thing, though JSON deserialization makes things just a bit more difficult because it doesn't run any constructors for the type you're using.
You could turn your class variables into properties and take ...
2
for this kind of task regex is the best instrument to use. Here is a link to test regex for your needs. You can also read an explanation for regex:
"(!Contract.)(.*)(?=})"
1st Capturing Group (!Contract.)
!Contract matches the characters !Contract literally (case sensitive)
. matches any character (except for line terminators)
...
2
I came up with the following. It is more or less an exact translation of the C# example from StackOverflow by Soner Gönül.
Note that it includes a boundary for the square root of the number being checked as there is no need to check higher factors.
Larger primes are going to be a challenge as divisibility by all odd numbers from 3 upward will be checked up ...
2
No, there is nothing out of the box for this requirement. You'll need to roll your own initializer.
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