I want to hide a specific picklist value(Closed) in the field stage (having picklist values- Open, Processing, Closed) the following code works fine for deleting first value.

However I am unable to delete second or third pick list value even though changing the position of id, any idea?

<apex:inputField value="{!Sales__c.Stage__c}" id="st">
<script type="text/javascript">
           var e = document.querySelectorAll('[id$="st"]')[0];
               if (e && !e[0].value) {e.remove(0);}

If the Closed satus will always be at the same position (i.e. third position), you can just call: e.remove(2); (the remove method expect the index position as parameter)

If you prefer to remove the option depending on its label (if the position can be changed), you can call:

  var inputStatus=document.querySelectorAll('[id$="st"]')[0];
  for (var i=0; i<inputStatus.length; i++){
     if (inputStatus.options[i].value == 'Closed' )
  • ah missed small logic i.e e.remove(2), Thank you Martin. Now it's working fine. – Laxman Mar 28 '17 at 13:08
  • You're welcome. Glad I could help ! – Martin Lezer Mar 28 '17 at 13:48

Finding by index is bad as you may also have none as an option.

Use below code if you'd like to remove the picklist option based on value:

<apex:page id="page">

    <apex:form id="form">
        <apex:selectList size="1" id="selectList">
            <apex:selectOption itemLabel="Open" itemValue="Open"/>
            <apex:selectOption itemLabel="Processing" itemValue="Processing"/>
            <apex:selectOption itemLabel="Closed" itemValue="Closed"/>

            (function() {
                // select DOM element
                var selectobject = 

                // iterate over option
                for (var i=0; i<selectobject.length; i++) {
                    // remove closed option matching its value
                    if (selectobject.options[i].value == 'Closed' ) {


Credits goes to this post from Stackoverflow.

$Component visualforce merge field is quite handy in such scenario.

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