Regular Expression in Apex to find entire link in string

Question

I have a regular expression in apex that is only grabbing part of the link I need in a string. I need it to grab the entire link.

Here is what im working with:

String myvar = 'this is an example http://test.com/testing/123654123';

String myvar1 = '(?:(?:(?:[a-z0-9]{3,9}:(?://)?)(?:[-;:&=+$,w]+@)?[a-z0-9.-]+|(?:www.|[-;:&=+$??,w]+@)[a-z0-9.-]+)((?:/[+~%/.w-]*)?\\??(?:[-+=&;%@.w]*)#?w*)?)';

            Pattern MyPattern = Pattern.compile(myvar1);

            Matcher MyMatcher = MyPattern.matcher(myvar);

            while (MyMatcher.find()) { 
                System.debug(MyMatcher.group());
                Location = MyMatcher.group();
        }

This is only returning http://test.com/

How can I modify the regular expression to provide the complete link?

Answer 1

You might try a few of the regexps mentioned in the article Detecting URLs in a Block of Text but the article also nails it by saying

The short answer is that it can’t be done. Pretty much any character is valid in URLs.

Answer 2

String myvar = 'this is an example http://test.com/testing/123654123';

String myvar1 = 'http'+myvar.split('http')[1];

System.debug(myvar1);