1

I am outputting a table from a list in my controller using apex:repeat.

In one of my columns, I want to have a link that will open the record for detail view

I want a link like this https://www.salesforce.com/apex/SystemChangeRequest?id=a3K8E0000000B7S.

as my detail page is called SystemChangeRequest and the id of the record is a3K8E0000000B7S

so I have tried this:

<td>                
    <apex:outputLink value="/apex/SystemChangeRequest/?id=!{Requests.id}">!{Requests.id}</apex:outputLink>                  
</td>

But the link being rendered in the browser is:

https://cs87.salesforce.com/apex/SystemChangeRequest/?id=!%7BRequests.id%7D

so it is giving an 'invalid URL' error.

So what am I missing or doing wrong?

1 Answer 1

4

You messed up your merge field; it should be {!Requests.Id}. Once you fix that, it should be okay. As an aside, I usually prefer the URLFOR formula, which is future-proof (it constructs the URLs correctly for you). That would look like this:

<apex:outputLink value="{!URLFOR($Page.SystemChangeRequest,null,[id=Requests.Id]}">
    {!Requests.Id}
</apex:outputLink>
2
  • +1 for URLFOR.
    – Adrian Larson
    Jan 4, 2016 at 18:15
  • 1
    N.B. merge field enclosed by apex:outputLink could be something more useful like {!Requests.Name} or some other user friendly value
    – cropredy
    Jan 4, 2016 at 19:04

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