Visual Force Page Error in salesforce

Question

I have Written the Visual Force Page Coding :

<apex:page standardController="Contact">
    <apex:form >
        <apex:pageBlock>
            <apex:pageBlockButtons location="top">
                <apex:commandButton action="{!Cancel}" value="Back"/>
            </apex:pageBlockButtons>
            <apex:pageBlockSection >
                <apex:pageBlockTable id="sampleGrid" value="{!Contact.AccountId}" var="a">
                    <apex:inputfield label="Account"  value="{!Contact.AccountId}" />
                </apex:pageBlockTable>
            </apex:pageBlockSection>
        </apex:pageBlock>
    </apex:form>
</apex:page>

output: it is Showing only one Grid line , but it is Not Displaying the lookupField on the Visual Force Page, How to Rectify the Error, Anyone Guide Me for the Answer

Answer 1

The way you use the pageBlockTable is little confusing as I see. You have to add apex:column tag in order to bring the columns of the table. Try below code for the table. This way you can add more columns to your table.

<apex:pageBlockTable id="sampleGrid" value="{!Contact.AccountId}" var="a">
    <apex:column >
        <apex:facet name="header">Account</apex:facet>
        <apex:inputfield label="Account"  value="{!Contact.AccountId}" />
    </apex:column>
</apex:pageBlockTable>

When you use pageBlockTable, the advantage is to bind dynamic values of a list into rows by using the value and var attribute value. Check the documentation linked. This is not being used in the code anyway. Hope you are in a mid of a development.