13
votes
Accepted
Replace Line Breaks (Multiple count as 1) in a string
This is a good time for replaceAll(regex, replacement):
String testString = 'Line 1\r\nLine 2\r\n\r\nLine 3';
system.debug(testString.replaceAll('(\\r|\\n)+', ' ** '));
Results:
Line 1 ** Line 2 *...
- 151k
13
votes
Accepted
lightning:input (text) - is it possible to have multiple patterns
Use the "OR" operator (|):
pattern="(\d{8}|[a-zA-Z0-9]{12}-\d{3})"
- 502k
12
votes
Accepted
How to get running class and method names programmatically?
Here's a fun fact to get the ball rolling: the constructor for any Exception class will generate the current stack trace (no need to throw). So you can, for instance, get the stack trace in your ...
- 151k
10
votes
How can I convert my htmlBody to plainTextBody using Apex/Regex
I think rather than using any RegEx, you can just use a built in String method: stripHtmlTags.
Salesforce String Class
So it would look like:
String plainText = htmlBody.stripHtmlTags();
- 2,218
10
votes
Regex Help- Escaping Characters And Matcher Method
The simplest solution is to use the \W character as your entire expression, it matches any non-word character. Unfortunately, this solution would also match any whitespace characters, and ignore the ...
- 151k
10
votes
Accepted
Regex Help- Escaping Characters And Matcher Method
You can match all punctuation using \\p{Punct}, as mentioned in the Pattern class, which matches:
!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
For example, the following code results in an empty ...
- 502k
9
votes
Accepted
Regular Expression matches returns false
The documentation on the Matcher class should shed some light here.
The description for matches() states the following
Attempts to match the entire region against the pattern.
Meanwhile the ...
- 64.1k
8
votes
Accepted
Lightning component regex doesn't work
The reason for this seems to be that the framework replaces the first line's asterisk character with the \u002A Unicode escape sequence before serving the files to the browser.
I'd report a bug if it ...
- 383
8
votes
Accepted
Split by /* act as regex?
Split actually expects a regular expression, so your split string is interpreted as "split when there are zero or more / characters" ("*" means "zero or more").
To avoid ...
- 502k
8
votes
Regex - Syntax error
Escape the \ with an extra \ . Like below:
AND(
!ISBLANK( Phone ),
!REGEX( Phone , '(([+][(]?[0-9]{1,3}[)]?)|([(]?[0-9]{4}[)]?))\\s*[)]?[-\\s\\.]?[(]?[0-9]{1,3}[)]?([-\\s\\.]?[0-9]{3})([-\\s\\.]?[0-...
- 1,860
7
votes
Accepted
Regex including curly brackets
Since backslashes are the escape character in Apex string literals, if you want a literal backlash, you need to escape it with a backslash.
So the right regex to use would be \\{.*\\}
- 64.1k
7
votes
Regular Expression matches returns false
It does work - but only if you use the method that yields a substring match.
String input = 'Inbound Call at 5:10:54 PM from 07970123123 (Jack Daniels)';
String regex = '(\\d{11}|\\d{5} \\d{6}|\\+\\d{...
- 93.7k
7
votes
Accepted
How to emulate SOQL LIKE matching in Apex?
Couldn't find code for this anywhere - many examples ignore the possibility of characters that have special meaning in regular expressions being present.
This is what I ended up with as a solution, ...
- 137k
7
votes
Accepted
SOQL query to fetch records with reserved characters ('*', '/', '(', ')')
The * character is not a special character as far as SOQL is concerned. Here's a trivial proof for you:
And here's the same in Apex:
System.debug(
Database.query(
'SELECT Name FROM ...
- 502k
6
votes
Regex Search-and-Replace with Capture Groups?
You can use $# to reference a capture group ($1 is the first, $2 is the second, etc.)
For your case I ran this:
System.debug('1a2'.replaceAll('(\\d)(\\D)(\\d)', 'first: $1; second: $2, third: $3'));
...
- 190
6
votes
Accepted
Issues with Regex matcher on APEX
There's two issues here: one is escaping the regex correctly, and one is the semantics of checking for a match. The following code works:
Pattern regex = Pattern.compile('(?m)([A-Z]{2,3})[\\s]+([0-9]+[...
- 93.7k
6
votes
Accepted
Invalid string literal '^.*\s(\d+)\s.*$'. Illegal character sequence \s' in string literal
Escape all the \ characters with more \ character of course!
private final String regex = '^.*\\s(\\d+)\\s.*$';
- 9,426
6
votes
Accepted
Regex implementation in Salesforce: getting from known string to end of the line
You need to turn on multi-line mode in order for the $ specifier to match at a line terminator (rather than at the end of the string). Multi-line mode is activated with the token (?m).
As Derek F. ...
- 93.7k
6
votes
Accepted
How do I replace all non-digit characters in a regex except for the period?
You can write a negated character class with ^ to include the period, ., and the set of digits, 0-9:
var z = x.replace(/[^0-9.]/g, '');
z is then "100.00".
- 93.7k
6
votes
Accepted
Using String.replaceAll() to remove character combination
You could use replaceAll with a regular expression as follows:
url = url.replaceAll('-+','-');
This says "match one or more (+) hyphens (-)" and we replace it with the singular hyphen (-).
- 502k
6
votes
Accepted
Why Salesforce does not accept my REGEX?
That's because SFDC matches the whole field against your REGEX, your whole Email__c is not only ';.+$', plus $ is a special character, so you need something like this
REGEX( Email__c, '.*[;.+$].*')
If ...
- 4,711
5
votes
Accepted
regular expression problem (Pattern/Matcher)
The matches method will only return true if the entire input string matches the result. You want to use find instead, which will match a substring. Take a look at the Matcher documentation for these ...
- 151k
5
votes
Accepted
How to create SUBSTITUTE function formula using REGEX
The formula syntax is not powerful enough to do as you wish. You would necessarily need to resort to a simple Apex Trigger. At a basic level, it would look something like this:
trigger ...
- 502k
5
votes
Accepted
Regular expression to check special symbols not working in lightning javascript
Try using the constructor syntax.
I've verified that this saves in lightning:
var regularExpression;
var re = new RegExp('[-!$%^&*()_+|~=`{}\[\]:";\'<>?,.\/]');
Note the escape of the ' ...
- 20.6k
5
votes
Accepted
Bug with parser in lightning bundle definition
For my usecase, I was able to find a workaround by doing a regex from a string instead of raw like so : var myWorkingRegex = new RegExp('/'); since you do not need to bound your regexes in a string ...
5
votes
Accepted
How to avoid System.StringException: No match found when only finding a substring and not a full match?
You're misreading the logs: the error in your "failure" code comes from calling Matcher.group (because there was no match).
Try the following:
String str = 'Text Messaging Plan (abc)';
Pattern p = ...
- 502k
5
votes
Accepted
Regex having issues in Apex
Apex Pattern class behaves like Java Pattern class. According to Java documentation you have to escape backslash if it is present in regex expression
The backslash character ('\') serves to ...
- 18.8k
5
votes
Accepted
Handling multiple regex matches in Ampscript
Not a pretty solution, but here's what I use:
%%[
SET @text = "<a href=""https://salesforce.stackexchange.com""target=""_blank"">Salesforce</a><a href=""https://stackoverflow.com"" ...
- 2,423
5
votes
Accepted
Regex for string but at least one character must be a number or letter
You'd just have to specify that there's a requirement of at least one letter or number somewhere in the string. Here's a possible solution:
^(\w| )*[0-9A-Za-z](\w| )*$
This says we must match zero ...
- 502k
5
votes
RegExMatch doesn't seem to be working correctly
Your regExmatch function is just going to return the match (in rendered HTML in your case), not do the replacements. Your pattern looks fine.
%%[
set @regEx = "<(.*?)>"
set @str = &...
- 31.1k
Only top scored, non community-wiki answers of a minimum length are eligible