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Salesforce Object Query Language (SOQL) does not support JOIN operations that SQL does. The reason for this is the multi-tenant nature of the Force.com platform. https://developer.salesforce.com/page/Multi_Tenant_Architecture SOQL does have a feature called Relationship Queries. https://www.salesforce.com/us/developer/docs/dbcom_soql_sosl/Content/...


5

For the above problem, I would suggest creating new Custom object, that will act as a Junction object between Roaster and Contacts. It will have look-up fields to Contact object and Roaster object. Now you need to write trigger on Roaster object, which will capture the Class Year and Class type details.Based on this, query on the Contact records and the ...


5

Your question seeks to relate a task/event to ONE Contact and MANY Accounts... and this is currently not possible. Many Contacts (and, by extension, each of their Accounts) is possible, but to relate it to one Contact and to many non-Contact objects is not available.


5

Most probably the relationship name is not Opportunity_and_License__c. You can verify this by clicking on the 'OfOpportunity' field label in the field list you copied in your question, and then use the 'Child Relationship Name' at the right side of the screen. Then add '__r' to that name. Probably something like Opportunity_And_License__r


5

Given that a single junction object points to a single license, then you should be able to follow that relationship in the sub query, e.g. SELECT Id, (Select OfLicense__r.dongle_id__c FROM Opportunities_and_Licenses__r) FROM Opportunity WHERE Id = '006M00000086xpw'


5

Here is one way: Id accountId = ...; Covenant__c[] covenants = [ select Id, Name, ... from Covenant__c where Id in ( select Covenant__c from CovenantJunction__c where Account__c = :accountId )]; Refer to the A Deeper look at SOQL and Relationship Queries on Force.com for more ...


4

With these association objects it usually works best to query the association object. You can then go up the parent relationships one or more levels (up to 5): Set<Id> dongleIds = new Set<Id>(); for (Opportunities_and_Licenses__c ol : [ select OfLicense__r.Dongle_id__c from Opportunities_and_Licenses__c where ...


4

To create Many-to-Many relationship you need Junction object(as you mentioned in your question). Lets take Opportunity and Product for example to explain this. If you want Opportunity A should have Product A and Product B, and Product A should be available in Opportunity A and Opportunity B you should have a Junction object to hold the relationship. So ...


4

The first master-detail relationship you create on your junction object becomes the primary relationship. This affects the following for the junction object records: Look and feel: The junction object's detail and edit pages use the color and any associated icon of the primary master object. Record ownership: The junction object records inherit the value of ...


4

Using the Unit of Work pattern backed up by the fflib-apex-common GITHUB library, you can delegate most of this work and make your coding somewhat simpler UnitOfWork will insert objects in a user-defined order so C2 will always be inserted before C3 (junction) Code would look something like this: ... build map of C1 suitable for location when building C3 ...


4

You can create a Unique field (Unique_Course_Student_Relationship__c) on the junction object and populate it with a concatenation of StudentId and CourseId through a workflow on create. CASESAFEID(StudentId) + CASESAFEID(CourseId) This will ensure that there's never two junction records with the same Student and Course as the value of that field needs to be ...


3

One solution is to use the technique illustrated in this answer. It amounts to adding a formula field to the objects that you are relating to each other that combines the various fields. You can then use that key in maps or in SOQL where Key__c in :keys and so limit the work you do to the actual permutations of those fields. On Opportunity, the Key__c ...


3

This is a good use case for leveraging an External ID field on the Catalog_Product__c object. The value that is contained in this field will be comprised of two keys concatenated together to create a unique value that represents the junction. In traditional database terminology this is known as a "compound key" and allows you to use a few bits of information ...


3

The trick is to set the saveUrl or the retUrl to the Id of the object you want the user to return. Is there a saveURL URL parameter set? If so, redirect to that. Is there a retURL URL parameter set? If so, redirect to that. Redirect to /home/home.jsp You have some options, the first one would be to override the New button just like this post illustrates. ...


3

Look at the following image I found on search engine: Here a team member is related to project. So there can be two scenarios: A team member can be related to multiple project A project can have multiple team members To achieve this we create a object which will have reference to team member and project to establish relationship. Let's say the object name ...


3

Unfortunately (or not?) it is only one level that can be cpecified in the query: In each specified relationship, only one level of parent-to-child relationship can be specified in a query. For example, if the FROM clause specifies Account, the SELECT clause can only specify the Contact or other objects at that level. It could not specify a child ...


3

If C is your junction object then C has a reference to an A and a reference to a B So in SOQL you could write something like thingC__c anExampleC = [select my_thing_A__r.thing_A_field__c, my_thing_B__r.thing_B_field__c from thingC__c where id = '.....'];


3

You should read through this Relationship Queries documentation that amongst other things explains the use of __r references. If you have these custom objects: A__c B__c C__c the field reference would be: C__c c = ...; Object aField = c.A__r.Field__c; Note that for standard objects e.g. Contact the reference fields don't follow this pattern but rather ...


3

Salesforce supports 2 kinds of relationships like Master Detail and Lookup. They are both one-to-many relationship, and they are both defined from the many-to-one side, that is from a child to a parent. They can be made one-to-one relationship by adding validation rules, or maybe triggers to enforce the one-to-one nature, i.e. only one child is allowed. ...


3

It may be worth creating a Developer Org if you haven't already and checking out the Force.com Platform Fundamentals guide which will take you through creating a recruitment application for a pseudo-company and covers this type of question. It's also a great introduction into earning the DEV-401 qualification! Let's go with this example. Picture having your ...


3

Ultimately, the best way to understand how these relationships work, is to try to create one in your Sandbox. This Salesforce Documentation is the only guide you need to follow. But this may be easier to understand if you consider how these relationships appear from a user's point of view. The user doesn't need to know that the Junction records exist. The ...


3

You might have demanded for permissions more than what is required for CRUD on junction object CI__c. Relation: CI__c(Jn) -> C__c(Master-Detail), I__c(Master-Detail) Check the field definitions of the Master Detail: If you have asked for Read/Write then you should have CRUD permission on C__c and I__c as well Change it two Read Only and try again, ...


3

Junction object is to achieve Many-to-Many relationship model in Salesforce. It means that each record can be associated with many records using the Junction object which keeps the reference of records. So, keep significance of junction object following things are required/considered:- Junction object must have reference of two different entities (object) ...


3

You can try something like this. Select Id,Name,(select Id,ContactId,Contact.Name from OpportunityContactRoles) from Opportunity


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What you're describing is a junction object. A junction object is the third object which represents a many-to-many relationship between two other objects. Your Group object would be a junction object between Account and Contact. Your objects may have a maximum of two Master-Detail relationships, which is a junction object defining a many-to-many ...


2

In general, your ability to change or delete things once included in a managed package is severely limited. Full details are available in the ISVForce Guide, specifically check out pages 20-38, which go over how metadata components can be edited and deleted by both the developer and subscribers. I haven't tried this myself, but according to the pg. 38, ...


2

If I understand the question correctly, this can be done without Visualforce using default layouts. Add OrderItem as a related list to your Order default layout. (Fields from Item can be included in the displayed fields.) Then the process could be: CSR creates and Order CSR clicks "New" on the OrderItem related list In the "New OrderItem" page, the Order ...


2

You can use the existing objects and relationships e.g. like this: select Id, ... from ShipmentLine__c where Shipment__c in (select Shipment__c from OrderLines__c where Id = :orderLineId) order by ... so in general no you do not need to introduce another relationship/junction object. Here is a good article on the subject of A Deeper look at SOQL and ...


2

It's Opportunity.Field__c and not Opportunity__r.Field__c. If you are on the same object, you don't even have to specify the object type. Another thing is, if your formula field is of a type string, you'll have to wrap your values in quotes, so in this case your formula should look like this: IF(RollUpSummaryField__c > 0, "abc", "xyz")


2

I would create separate many-to-many objects, any other solution would also remove standard many-to-many features as you can only create 2 master-detail relationships. Sure you could have a custom object with a lot of lookup's that you re-use, what your choice and solution should come down to is essentially based on what functionality and features you truly ...


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