Is it possible to convert an SOBject to a Map in a very few short lines of codes?

  • 3
    Do you mean a list of SObject's? If so, Map<ID, SObject> myMap = new Map<ID, SObject>(mySObjectList); Will give you a map of SOBject's by Id. Feb 21, 2013 at 12:09
  • 1
    An Sobject has some of the behaviour of a Map<String,Object> - i.e. get/put methods. What are your reasons for wanting to convert an Sobject to a Map<String,Object> (I presume that's what you're after)? Feb 21, 2013 at 12:16

3 Answers 3


The question is not very clear, but you could do something with the JSON.deserializeUntyped method as following:

testobject__c  tObj =  [SELECT boolfield__c,currencyfield__c,datetimefield__c,formulafield__c,Id,Name,numberfield__c,textfield__c,url_field__c FROM testobject__c limit 1];

Map<String, Object> m = (Map<String, Object>) JSON.deserializeUntyped(JSON.serialize(tObj));


I however somewhat assume that if you are going to to this in an interative fashion, or for bulky objects, this is not very performant, and you should take this into consideration. Be sure to know why you want to do this in your logic, and consider possible alternatives.

update: Salesforce released an apex native method to accomplish this. See dana's answer.

  • 1
    nice use of deserializeUntyped! +1 Feb 21, 2013 at 12:45
  • 3
    Nice smart answer, though agree with "Be sure to know why..." Feb 21, 2013 at 13:33

The sObject has a native function getPopulatedFieldsAsMap that converts from an sObject to a Map<String,Object>. This was released in Summer '16 which is probably why the other answers resort to using JSON serialization to accomplish this.

Account a = new Account();
a.name = 'TestMapAccount1';
insert a;
a = [select Id,Name from Account where id=:a.Id];
Map<String, Object> fieldsToValue = a.getPopulatedFieldsAsMap();

for (String fieldName : fieldsToValue.keySet()){
    System.debug('field name is ' + fieldName + ', value is ' +

// Example debug statement output:
// DEBUG|field name is Id, value is 001R0000003EPPkIAO
// DEBUG|field name is Name, value is TestMapAccount1

It's doable if you de/serialize to JSON. The below may work but Sdry's untyped approach is superior:

Contact contactObject = new Contact(
  FirstName = 'Derp',
  LastName  = 'Herpinson'

String data = System.Json.serialize(contactObject);

Map<String,String> contactMap = (Map<String,String>)System.Json.deserialize(
  data.substringBefore('"attributes":{') + data.substringAfter('},'),

//{FirstName=Derp, LastName=Herpinson}

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.