Given the next code:

    Object deserializeResponse = JSON.deserializeUntyped(response);
    System.debug('DESERIALIZERESPONSE' + deserializeResponse);
    //DESERIALIZERESPONSE: {proposalIds=null, response=true}
    System.assert(deserializeResponse.response ==true);

I need to access to response property of the deserializeResponse Object. How can I do it? Because, right now, I have the next compilation error: Variable does not exist: response

2 Answers 2


You are using deserializeUntyped, that means, deserializeResponse as Object does not know about its structure during compilation. Try this approach:

Map<String, Object> deserializeResponse = (Map<String, Object>) JSON.deserializeUntyped(response);
System.assert((Boolean) deserializeResponse.get('response'));
  • Simple but effective. Thank you so much!
    – CPS
    Dec 10, 2021 at 12:56
  • 2
    The Object knows about its structure at runtime, but the compiler does not know at compile-time, hence the need to cast.
    – sfdcfox
    Dec 10, 2021 at 12:58

The Object type is not really something we can use directly in Apex. I don't believe it has any fields/properties, and only has a few known (but undocumented) methods.

The generally preferred approach to deserializing JSON in Apex is to create a series of classes that match the structure of the JSON you're trying to deserialize.

In this case, that would look something like this:

public class MyJsonData{
    public List<Id> proposalIds;
    public Boolean response;

// Even though we're telling JSON.deserialize() to use MyJsonData as a template
//   of sorts, it always returns an Object, so we need to do a little type-casting
MyJsonData data = (MyJsonData)JSON.deserialize(response, MyJsonData.class);

// When working with booleans, there is no need to test for equality to true
//   (or false, either).

JSON.deserializeUntyped() is generally used when your JSON data contains something problematic for Salesforce like a reserved word (break, continue, switch) or things like __c.

deserializeUntyped() also returns an Object, but it actually is either a Map<String, Object> or a List<Object>, depending on whether the topmost element in the JSON is a (JSON) object or a list. In your case, you'd get a Map<String, Object>.

Using a Map<String, Object> can involve a lot of extra type-casting (which is why at least I prefer defining classes for the deserialization), but in your case would be fairly simple.

Map<String, Object> data = (Map<String, Object>)JSON.deserializeUntyped(response);

Boolean jsonResponse = (Boolean)data.get('response');

  • 1
    So instructive, I've learned a little bit more about Object, Serialize, JSON, and so on... Thank you!
    – CPS
    Dec 10, 2021 at 12:57
  • As you say, Object has no properties, and two methods, equals and hashCode. JSON.deserializeUntyped can also return a String, Boolean, Decimal, or null value as well. Overall, nice work, though.
    – sfdcfox
    Dec 10, 2021 at 12:57

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