Given the following:

String a = '{"field":13316956360165196849}';
Map<String, Object> tokenObject = (Map<String, Object>) JSON.deserializeUntyped(a);

I get the error:

System.JSONException: For input string: "13316956360165196849" at [line:1, column:2]

However if I remove the last digit it deserializes fine

String a = '{"field":1331695636016519684}';
Map<String, Object> tokenObject = (Map<String, Object>) JSON.deserializeUntyped(a);

Any idea why having one character longer causes JSON to choke? Right now I do not have a work around and looking to get more info on what may be the cause

  • 32-bit integer limit, perhaps? – Derek F Feb 20 at 17:31
  • @DerekF Yea I was thinking that and if that is the case the only way around it will be to use regex to remove that field/value from the JSON. Im checking now to see if it is critical the value be present downstream....I have no control over the type so cannot get it change to a string – Eric Feb 20 at 17:32

My comment was close, this is an issue because the integer literal 13316956360165196849 overflows the 64-bit long

Max value for a long:
9,223,372,036,854,775,807 (10^18)

Your value:
13,316,956,360,165,196,849 (10^19)

| improve this answer | |
  • but the error For input string: "13316956360165196849" makes me think it was trying to deserialize it into a string due to the error? Or maybe just a bad message – Eric Feb 20 at 17:35
  • So basically the only way around is to remove it from the JSON string? A class to deserialize into is a worse option as a lot of the field names have . in them so I would still have to do a lot of manipulation or yuk write a parser. – Eric Feb 20 at 17:36
  • 2
    It'd be hard to represent a number too large for the platform to handle as anything other than a string in an error message though, and a value in JSON that isn't quoted and isn't true/false must be a number, yeah? – Derek F Feb 20 at 17:39
  • Makes sense. Removal it is – Eric Feb 20 at 17:40
  • Is there possibly a way to do a partial typed deserialization? Something that says "treat this one field as a string, and then deserialize everything else as a Map<String, Object>"? – Derek F Feb 20 at 17:40

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