Is it possible to access all of an objects fields through the schema class using a string? I know we can do this with an id.

Schema.DescribeSObjectResult sor = id.getSobjectType().getDescribe();

Is there a method by which we can do the following:

Schema.DescribeSObjectResult sor = 'Account'.getSobjectType().getDescribe();

Yes, you just pull the SObjectType out of the global describe.

SObjectType accountType = Schema.getGlobalDescribe().get('Account');
DescribeSObject accountDescribe = accountType.getDescribe();

Note that calling getGlobalDescribe() is quite CPU intensive and should be avoided in any sort of loop. Typically, if I expect to be retrieving a high volume of describes, I still implement a DescribeCache to save on this limit. In addition to performance, it also facilitates mocking if you make the class/methods virtual. It typically looks something like below:

public with sharing class DescribeCache
    static Map<String, SObjectType> objects = Schema.getGlobalDescribe();
    public static SObjectType getSObjectType(String objectName)
        return objects.get(objectName);

    static Map<SObjectType, Map<String, SObjectField>> fields =
        new Map<SObjectType, Map<String, SObjectField>>();
    public static SObjectField getField(String objectName, String fieldName)
        return getField(getSObjectType(objectName), fieldName);
    public static SObjectField getField(SObjectType sObjectType, String fieldName)
        if (sObjectType == null) return null;
        if (!fields.containsKey(sObjectType))
            fields.put(sObjectType, sObjectType.getDescribe().fields.getMap());
        return fields.get(sObjectType).get(fieldName);

Not quite like your example, but yes, this is possible.

One approach involves the Type class, which provides the little bit of reflection that the Apex language currently has.

Type t = Type.forName('Account');
SObject sobj = (SObject)t.newInstance();

DescribeSObjectResult accountDescribe = sobj.getSObjectType().getDescribe();

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.