lstIQCodes = IQcodeString.replaceAll(' ','').split(','); 

I have tried the above code and able to replace spaces and now I want to replace newline as well.

3 Answers 3


If you just want to get rid of all the white space, you can just delete it:

lstIQCodes = IQcodeString.deleteWhitespace().split(','); 

ReplaceAll actually takes a regular expression for the first parameter, so the following is also valid:

lstIQCodes = IQcodeString.replaceAll('\\s+','').split(','); 

\\s refers to all white space, including tabs, new lines, carriage returns, and spaces.

Or, if you really just wanted spaces and newlines:

lstIQCodes = IQcodeString.replaceAll('[\\n ]+','').split(','); 
  • 1
    Exactly what I would have recommended as well. Using split is not really appropriate.
    – Adrian Larson
    Jun 26, 2018 at 6:32

You can follow the same approach to remove the new lines as well

for(String lines : IQcodeString.replaceAll(' ','').split(','))
     system.debug(lines.replaceAll('\n','').replaceAll('\r','') );

Here is a sample utility function for this specifically because of the presence of the legacy carriage return character (ASCII 13) I was seeing in data.

  public static String removeAsciiCharFromString(String str, Integer c) {
    String ret = '';
    List<Integer> chars = new List<Integer>();
    for (Integer i = 0; i < str.length(); i++) {
      if (str.charAt(i) != c) {
    ret = String.fromCharArray(chars);
    return ret;


    String test = String.fromCharArray(new List<Integer> { 65, 13, 65 });
    String expected = 'AA';

    String actual = UtilConvert.removeAsciiCharFromString(test, 13);

    System.assertEquals(expected, actual);

Of course you can pass in any ASCII value, such as 32 for whitespace.

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