I am using regex to find line which starts with 'aaaa'
pattern myPattern = pattern.compile('^(aaaa)\b.*');
String a = 'aaaa,777,ttttt,rrrrrr';
a += '\n' + 'tttttt,ttttt,0000';
matcher myMatcher = myPattern.matcher(a);
System.debug(myMatcher.matches());
System.debug(myMatcher.groupCount());
System.debug(myMatcher.group());
System.debug(myMatcher.group()); this line is throwing exception no group is found. I have tested my regex at website https://www.freeformatter.com/java-regex-tester.html
Can any one tell me what i am doing wrong here.