1

Is it possible to replaceall on a string using wildcards? For example 

string adder;
adder = '[Test | 123 ! xyz]';
string replaced;
replaced = adder.replaceall('|%!','');

System.AssertEquals(replaced,'Test xyz');

Here I am using % as wildcard but it is not working.

|improve this question|||||
1

The documentation for the replaceAll() method says that it accepts a Regular Expression as the first argument. If you wanted to get rid of everything between | and ! inclusive you can use adder.replaceAll('(\\|.*!)','');.

|improve this answer|||||
  • What I want to do is something like this: [Term: 1 | Vol: 1| Result:1][Term:2|Vol:2|Result:2] and if i want to grab all the terms do ReplaceAll('| Vol: % ]',']') so the result is [Term:1][Term:2] – AverageJoeVBA Jun 23 '17 at 18:37
  • @AverageJoeVBA As stated in the answer (implicitly), you need to "escape" |, which normally means "OR", and you also need to escape the "\" that you use to escape the |, because that has special meaning in Apex Code (also an escape), so you have to write \\| to match a literal | character. – sfdcfox Jun 23 '17 at 18:43
  • Awesome Jeff thanks for the updated answer. Worked to perfection, saved me some rework of splitting out the build of a string throughout a controller. – AverageJoeVBA Jun 23 '17 at 18:44
  • I edited my comment once I re-read the question. The link I posted for Regular Expressions is a good place to get started, but each regex is going to be unique to the situation. In the example you just gave you would use replaceAll('(\\s?\\|[^\\]]*)','') – Jeff Bennett Jun 23 '17 at 18:45
  • Haha @AverageJoeVBA sorry I got distracted trying to build a new RegEx for you. Glad I could help. Leaving the new RegEx up though in case anyone else wants it. – Jeff Bennett Jun 23 '17 at 18:46

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.