Calculating number of digits in the integer part in a decimal number

Question

Currently I want to find out the number of digits in the integer part of a decimal number.

system.debug((895.95).intValue().format().length());

I am getting correct value as 3.

Just wanted to know if there is any direct function available or better way to do this ?

Answer 1

Here you go:

Decimal x = -85695.95;
system.debug(x.precision() + ' - ' + x.scale()); // you want (x.precision() - x.scale())

where Decimal methods:

scale() Returns the scale of the Decimal, that is, the number of decimal places.

precision() Returns the total number of digits for the Decimal.

Answer 2

Sure, if you want to stick with numbers, this Execute Anonymous script illustrates a different approach.

static Integer length(Decimal input)
{
    return (input == 0) ? 1 : 1 + (Integer)Math.floor(Math.log10(Math.abs(input)));
}
system.assertEquals(3, length(895.95));

Note that you log10(0) is infinity, so you need to handle that edge case. You can also add null handling if you wish. Anyway, log10 basically gives you the number of tens places you have minus one. With negative numbers, you'll get a NaN value, so you have to take the absolute value.