I am curious to know, is there any way exists from where we can know that a particular id is of type VF/class/trigger/components etc.

The way I think/know currently is, to query with "ApexPage" to check whether it is a page, "ApexClass" to check for class.

Is there any single/more prominent way to know this?

Thanks in advance.!


5 Answers 5


You can use Id.getSObjectType() to know what type an Id is.

Id someId = ...;

You can refer to it literally:

if(someId.getSobjectType() == ApexClass.sObjectType) {
    // is a apex class

Or you check as a string:

if(String.someValueOf(someId.getSObjectType()) == 'ApexClass') {
    // is an apex class

You can get to know it from the first three digit key prefix whether its a Apex Class, VF Page or Trigger

Apex Class - 01p
VF Page - 066
Apex Trigger - 01q
  • Does these prefix are common across all salesforce orgs? For my org as well, there are same.
    – Ysr Shk
    Nov 23, 2016 at 6:48

There is a better way to do this such that it is dynamic i.e. works for any component and is reusable. The reusable apex method is available as an official salesforce knowledge article -- How to find Object Type from Record ID Prefix

Also, it is highly recommended to go through the apex doc for the following methods and understand their return types:

  • Searching the entire global describe can easily consume several seconds of CPU time, though.
    – sfdcfox
    Nov 23, 2016 at 6:47

You can find out the Id type in the following way:

Account a = new Account(Name = 'account');
insert a;
Id myId = a.id;
System.assertEquals(Schema.Account.SObjectType, myId.getSobjectType());

This would work for all sObject Types It would return Class as ApexClass, VF Page as ApexPage etc.


Small code snippet of how to get all object prefixes in the org.

 for ( Schema.SObjectType ot : (Schema.SObjectType[])Schema.getGlobalDescribe().values() ) {
        Schema.DescribeSObjectResult dor = ot.getDescribe();
        System.debug('--->>> Prefix: ' + dor.getPrefix() + '; Object: ' + dor.getName() + ';');

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