I can retrieve a data extension from exact traget using something like this:

SoapClient client = new SoapClient();

using (new OperationContextScope(client.InnerChannel))
    MessageHeader<string> header = new MessageHeader<string>(ExactTargetToken);
    var untyped = header.GetUntypedHeader("fueloauth ", "http://exacttarget.com");

    RetrieveRequest req = new RetrieveRequest();

    req.Properties = new string[] { "TheKeyIUse", "Email" };
    req.ObjectType = "DataExtensionObject[TheDataExtensionName]";
    req.Filter = new SimpleFilterPart() { Property = "TheKeyIUse", SimpleOperator = SimpleOperators.equals, Value = new[] { "someValue" } };
    string msg;
    APIObject[] apiObj;

    client.Retrieve(req, out msg, out apiObj);

Now I need to receive the content of a "publication list". Is that possible through the Soap Api?

Edit: The request that gets the PublicationList is

<s:Envelope xmlns:s="http://www.w3.org/2003/05/soap-envelope" xmlns:a="http://www.w3.org/2005/08/addressing">

        <fueloauth  xmlns="http://exacttarget.com">mykey</fueloauth >

    <s:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
        <RetrieveRequestMsg xmlns="http://exacttarget.com/wsdl/partnerAPI">

1 Answer 1


The API Object for a Publication List is simply a List, with a ListClassification property value of PublicationList.

Object details: List

Some code samples: Retrieving a List from an Account

Here's the C# snippet from the page:

RetrieveRequest rr = new RetrieveRequest();
rr.ObjectType = "List";

SimpleFilterPart sf = new SimpleFilterPart();
sf.SimpleOperator = SimpleOperators.equals;
sf.Property = "ListName";
sf.Value = new String[] { listName };

rr.Filter = sf;

rr.Properties = new string[] { "ID", "ListName", "ListClassification" };

status = framework.Retrieve(rr, out requestID, out result);

List l = (List)result[0];
  • This worked. It resulted in a request like i added to the question. I actually need to rceive the subscribers insde of a publicationList. I create a new question for that.
    – Mathias F
    May 31, 2016 at 14:38

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