I need to have a JSON Formatted Base64 for this, but I am not sure how to change this string to have it as Base64 JSON Format.
public String requestBody = '{["Um05dkxFSmhjZz09"]}';
Um05dkxFSmhjZz09 this is already in Base64
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Why do you need your JSON to be base64?– Adrian Larson ♦Commented Mar 1, 2016 at 17:37
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@AdrianLarson its for my test class Fake respond, and I receive String M = (String)JSON.deserializeStrict(responseBody,String.class); b = EncodingUtil.base64Decode(M); in my class, so my test string needs to be in that format– MetawaaCommented Mar 1, 2016 at 17:39
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I am really confused with data structure inside string, it looks like a Hash Map without key but an array– karthikselvaCommented Mar 1, 2016 at 17:41
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@karthikselva its a fake response– MetawaaCommented Mar 1, 2016 at 17:42
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do you want to create Base64 encoded value of 'Um05dkxFSmhjZz09'?? or the whole String '{["Um05dkxFSmhjZz09"]}'?– ipradhanskCommented Mar 1, 2016 at 17:44
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3 Answers
Encoding/Decoding is different from Serialization/Deserialization
- The JSON you have for fake response is malformed.
- If all you are getting from the response is Base64 encoded string, you don't need to deserialize
- So in this case there is no need for JSON at all
Try this instead:
public String requestBody = 'Um05dkxFSmhjZz09';
b = EncodingUtil.base64Decode(requestBody);
answered Mar 1, 2016 at 17:45
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1Thank you for the respond I just use this to make it JSON String formatJSON = JSON.serializePretty(requestBody);– MetawaaCommented Mar 1, 2016 at 17:55
A JSON works in a key-value pair.
When you are creating JSON here, I see the value, but not the key. Hence the solution would be to create a key-value pair instead.
Like:
public String requestBody = '{"yourkey": "Um05dkxFSmhjZz09"}' //This is a JSON String
If you intend to use an array of values, use:
public String requestBody = '{"yourkeys": ["Um05dkxFSmhjZz09"]}'
and to validate any JSON in future, you could always use JSONLint
answered Mar 1, 2016 at 17:52
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1Thankyou for the respond , I actually didnt know I could make it format it to json by String formatJSON = JSON.serializePretty(requestBody); it worked just fine– MetawaaCommented Mar 1, 2016 at 17:55
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I posted the answer as well , I am not sure if its okay, but you gave a lot of good information thank you– MetawaaCommented Mar 1, 2016 at 18:01
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1its perfectly OK. you can mark your answer as best answer after 2 days... :) Commented Mar 1, 2016 at 18:20
in test cases we can actually use Base64 and do
String formatJSON = JSON.serializePretty(requestBody);
to turn it into Json
