I have written apex class.variable declaration is:
public string QPA$MV2 {get;set;}
It shows error:
Error: Compile Error: Invalid identifier: QPA$MV2 at line 254 column 23 How to resolve it ?
1 Answer
All class/property/method identifiers must be alphanumeric and cannot contain the underscore (_) character twice in a row. At least for class, you can find a good description of the rules:
The name can only contain characters, letters, and the underscore (_) character, must start with a letter, and cannot end with an underscore or contain two consecutive underscore characters.
I think by characters, letters, and the underscore (_) character, they meant numbers, letters, and the underscore (_) character.
Your original post made no mention of JSON, but you can find solutions to that problem here.
answered Feb 26, 2016 at 5:59
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@uma It makes the identifier invalid. Use only numbers, letters, and underscores./– Adrian Larson ♦Feb 26, 2016 at 6:03
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I have generated a class from JSon.Usion JSON to Apex converter I generated the class.it gives the variable as "public double QPA$MV2 {get;set;}" while saving it shows error.– uma451Feb 26, 2016 at 6:04
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@uma - See the link Adrian included. Apex names cannot have $. If the Json2Apex generator gave you invalid variable names, change them to valid ones and use the techniques in the link to fix up the json before you deserialize– cropredyFeb 26, 2016 at 6:41
map<String,String>this will solve your issue .. check this post I had same issue before salesforce.stackexchange.com/questions/100667/…